Question 673236
a) {{{sqrt(3)/sqrt(15) = sqrt(3)/sqrt(3*5) = sqrt(3)/(sqrt(3)*sqrt(5)) = 1/sqrt(5) = (sqrt(5)*1)/(sqrt(5)*sqrt(5)) = sqrt(5)/5}}}
  
b) {{{sqrt(8)/sqrt(12) = sqrt(4*2)/sqrt(4*3) = (sqrt(4)*sqrt(2))/(sqrt(4)*sqrt(3)) = (2*sqrt(2))/(2*sqrt(3)) = sqrt(2)/sqrt(3) = (sqrt(3)*sqrt(2))/(sqrt(3)*sqrt(3)) = sqrt(6)/3}}}