Question 60893

{{{sqrt((4x-5)^2)=+-sqrt(-32)}}}
{{{4x-5=+-sqrt(-16)*sqrt(2)}}}
4x-5=+-{{{4i*sqrt(2)}}}
4x=5+-{{{4i*sqrt(2)}}}
{{{x=(5-4i*sqrt(2))/4}}} and {{{x=(5+4i*sqrt(2))/4}}}
Happy Calculating!!!