<PRE><B>Question 672933</B>
solve the following systems of equations? 
3x-2y+2z=-2
x+6y-2z=-2
x+2y=0 
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Rearrange:
x + 2y + 0  = 0
x + 6y - 2z = -2
3x- 2y + 2z = -2
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Subtract 1st from 2nd.
Subtract 3 times 1st from 3rd
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x + 2y + 0  = 0
0 + 4y - 2z = -2
0 - 8y + 2z = -2
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Add 2 times 2nd eq. to 3rd
x + 2y + 0  = 0
0 + 4y - 2z = -2
0 +  0 - 2z = -6
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z = 3
---
4y = 4
y = 1
----
x  = -2
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Cheers,
Stan H.




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