Question 672160
Perpendicular lines have negative inverse slopes.
{{{highlight_green(y=5x+3)}}} has a slope of 5
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Using {{{-1/5}}} and (-4, 5),
y - 5 = {{{(-1/5)(x--4)
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y - 5 = {{{(-1/5)x + (4/5)}}}
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y - 5 + {{{(1/5)x - (4/5) = 0
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{{{(1/5)x + y - 5(5/5) - (4/5) = 0}}}
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{{{highlight((-1/5)x + (29/5))}}}
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{{{graph(300,200,-10,10,-10,10,(-1/5)x+(29/5),5x+3)}}}

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