Question 672800
find four consecutive odd integers such that twice the sum of the first two is 56 greater than the sum of the third and the fourth. 
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1st: 2x-3
2nd: 2x-1
3rd: 2x+1
4th: 2x+3
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Equation:
2(4x-4) = (4x+4)+56
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8x-8 = 4x + 60
4x = 68
x = 17
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1st: 2x-3 = 31
2nd: 33
3rd: 35
4th: 37
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Cheers,
Stan H.
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