Question 672676
{{{(x-3)^2 = 25}}}


{{{sqrt((x-3)^2) = sqrt(25)}}}

s0lutions:

{{{x-3 = 5}}} or {{{-(x-3) = 5}}}

if {{{x-3 = 5}}}, then

{{{x= 5+3}}}

{{{x= 8}}}


if {{{-(x-3) = 5}}}, then

{{{-x+3= 5}}}

{{{-x= 2}}}

{{{x= -2}}}


or, you can do it this way:

{{{(x-3)^2 = 25}}}

{{{x^2-6x+9 = 25}}}

{{{x^2-6x+9-25=0}}}

{{{x^2-6x-16=0}}}...use quadratic formula


 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


 {{{x = (-(-6) +- sqrt( (-6)^2-4*1*(-16) ))/(2*1) }}}


 {{{x = (6 +- sqrt(36+64 ))/2 }}}


 {{{x = (6 +- sqrt(100 ))/2 }}}


 {{{x = (6 +- 10)/2 }}}


solutions:


 {{{x = (6 + 10)/2 }}}

{{{x = 16/2 }}}

{{{x = 8 }}}

or

{{{x = (6 -10)/2 }}}

{{{x = -4/2 }}}

{{{x = -2 }}}





{{{ graph( 600,600, -10, 10, -30, 10, (x-3)^2-25) }}}