Question 672670


{{{r + 3/r = -4}}}......first both sides multiply by {{{r}}} to eliminate 

{{{r}}} out of denominator


{{{r*r + 3*r/r = -4*r}}}


{{{r^2 + 3= -4r}}}.....move {{{-4r}}} to the left


{{{r^2+4r + 3= 0}}}.........use quadratic formula to solve for {{{r}}}


{{{r= (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 


{{{r= (-4 +- sqrt( 4^2-4*1*3 ))/(2*1) }}} 


{{{r= (-4 +- sqrt( 16-12 ))/2 }}} 


{{{r= (-4 +- sqrt( 4 ))/2 }}} 


{{{r= (-4 +- 2)/2 }}} 


solutions:

{{{r= (-4 + 2)/2 }}} 

{{{r= -2/2 }}} 

{{{highlight(r= -1) }}} 


{{{r= (-4 - 2)/2 }}} 

{{{r= -6/2 }}} 

{{{highlight(r= -3) }}}