Question 672599


if {{{(2b-3)}}} is one factor, then {{{(2b+3)}}} must be second factor

multiply both factors

{{{(2b-3)(2b+3)=2b*2b+2b*3-3*2b-3*3=4b^2+6b-6b-9=4b^2+cross(6b)-cross(6b)-9=4b^2-9}}}