Question 672537
{{{3x-y+5=0}}} and {{{6x-2y-7=0}}}


{{{3x+5=y}}}

{{{6x-7=2y}}}...=>..{{{3x-3.5=y}}}

 {{{ graph( 600,600, -10, 10, -10, 10, 3x+5, 3x-3.5) }}}

now use distance formula and find the distance between one point on 

{{{3x+5=y}}} and one on {{{3x-3.5=y}}}


easiest way is to find {{{x-intercept}}} or {{{y-intercept}}}

let use {{{x-intercept}}} because lines are parallel and slopes are positive 

and find {{{x-intercepts}}}


{{{3x+5=y}}}....=>....{{{3x+5=0}}}..=>..{{{3x=-5}}}..=>..{{{x=-5/3}}}...=>..{{{x=-1.17}}}

{{{x-intercept}}} is at ({{{-5/3}}},{{{0}}})


{{{3x-3.5=y}}}....=>....{{{3x-3.5=0}}}..=>..{{{3x=3.5}}}..=>..{{{x=1.17}}}..=>.{{{x-intercept}}} is at ({{{1.17}}},{{{0}}})


find the distance (note the distance between these two points is equal to the distance between given two lines)


*[invoke hummingbird_distance_2D 1.17, 0, -1.17, 0]