<PRE><B>Question 672588</B>
Can you help me to solve Trig equations algebraically?
3tan^3(t)-3tan^2(t)-tan(t)+1=0
What I have so far, if correct;I changed my tan(t) to (x) for less confusion
[3tan^3(t)-3tan^2(t)] -tan(t)+1=0
(3x^3-3X^2)-1x+1 = 0
3x(x^2-x)-1(x+1)= 0 pull out the common factor and then stuck!
---------------
Make it
3x^2(x - 1)-1(x+1)= 0
{{{(3x^2-1)(x-1)}}} = 0
</PRE>