<PRE><B>Question 60863</B>
Given  4x^2+ 2x -3 = 0
              Get all the “x” terms to one side and terms on the other side.
              We get
              4x^2 + 2x = 3
              Let us make the above equation even.
              Multiply the above equation by 4.
              16x^2 +8x  = 12
              Add one on both sides.
              16x^2 + 8x + 1 = 12 +1
              16x^2 + 4x + 4x + 1 = 13
              4x( 4x +1) +1(4x +1) = 13
              (4x +1)^2 = 13
              Taking square root on both sides, we get
              4x +1 = + Sqrt(13)
              Subtract 1on both sides, we get
              4x = + Sqrt(13) -1
              Rearrange the above, we get
              4x = -1 + Sqrt(13)
              Divide by 4 in the above equation, we get
              x = [-1 + Sqrt(13)] / 4
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