Question 60855
To whom may it concern, 
I have trouble to do this question. 
From a point at the same level as the foot of a building 50 metres high, the angle of elevation of its top is found to be 52.83°. Find the distance of the point of observation from the top of the building. 
Please help and thank you. 
LET THE TOP OF BLDG BE 'T' AND BOTTOM BE 'B'.LET THE POINT OF OBSERVATION BE 'P'
PBT IS RIGHT ANGLED TRIANGLE WITH ANGLE PBT = 90 AND ANGLE TPB = 52.83 DEGREES AND TB=50 M.
TAN(52.83) = TB/PT = 50/PT
PT = 50/TAN(52.83)= 37.95 M