Question 60863
Okay it says to solve by completeing the square.
4x^2+2x-3=0
So far I have the following:
4x^2+2x=3
x^2+2/4x=3/4
X^2+X/2-3/4=0..........MAKE PERFECT SQUARE USING X^2 AND X TERMS WITH THE FORMULA (X+A)^2 = X^2+2XA+A^2...THAT IS 2XA=X/2.....2A=1/2...A=1/4....
NOW ADD AND SUBTRACT A^2...THAT IS (1/4)^2....
=[(X)^2 + 2(X)(1/4)+(1/4)^2]-(1/4)^2-3/4=0
= [X + (1/4)]^2= 1/16 +3/4 = 13/16
X+1/4 = + OR - SQRT(13)/4
X = -1/4 + OR - SQRT(13)/4 = [-1 + OR - SQRT(13)]/4


Then I get totally lost and don't know what else to do!! HELP! PLEASE!
Thanks in advance!!!!!!