Question 672492
{{{ 4^x + 6*4^(-x)  = 5 }}}
You can say {{{ z = 4^x }}}
{{{ z + 6/z = 5 }}}
{{{ z^2 + 6 = 5z }}}
{{{ z^2 - 5z + 6 = 0 }}}
{{{ ( z - 2 )*( z - 3 ) = 0 }}}
{{{ z = 2 }}}
{{{ z = 3 }}}
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{{{ 4^x = 2 }}}
{{{ x = 1/2 }}}
and
{{{ 4^x = 3 }}}
{{{ x*log(4) = log(3) }}}
{{{ x = log(3) / log(4) }}}