Question 672468
Let {{{ a }}} = amount invested @ 11.2%
Let {{{ b }}} = amount invested @ 14%
given:
(1) {{{ a + b = 10800 }}}
(2) {{{ .112a = .14b }}}
-------------------
(2) {{{ 112a = 140b }}}
(2) {{{ a = (140/112)*b }}}
(2) {{{ a = 1.25b }}}
Substitute this result into (1)
(1) {{{ 1.25b + b = 10800 }}}
(1) {{{ 2.25b = 10800 }}}
(1) {{{ b = 4800 }}}
and, since
(1) {{{ a + b = 10800 }}}
(1) {{{ a + 4800 = 10800 }}}
(1) {{{ a = 6000 }}}
$6,000 should be invested @ 11.2%
$4,800 should be invested @ 14%
check:
(2) {{{ .112a = .14b }}}
(2) {{{ .112*6000 = .14*4800 }}}
(2) {{{ 672 = 672 }}}
OK