Question 60864
3x^2-6x=3
Not sure if I am doing this right, but so far I have
3x^2-6x-3=0...OK
x^2-3x-1=0...DIVIDING WITH 3 WE GET X^2-2X-1=0...COMPARING WITH STD EQN.
AX^2+BX+C=0.....WE HAVE A=1,B=-2,C=-1
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-(-2) +- sqrt( (-2)^2-4*1*(-1) ))/(2*1) }}}
{{{x = (2 +- sqrt( 4+4 ))/(2) }}}
{{{x = (2 +- sqrt( 8 ))/(2) }}}
{{{x = (1 +- sqrt( 2 )) }}}


Am I on the right track?
Can you help me with the rest?
Thanks so much!