Question 672484
{{{x^2+16=-49}}} we solve by the squaring method

When we add 64 then we get a perfect square on the left side of the equation

{{{x^2+16x+64=64-49}}}


{{{(x+8)^2=15}}}

Take the square root on both sides
(x+8) = +/- {{{sqrt(15)}}}

x= -8+{{{sqrt(15)}}} OR x=-8-{{{sqrt(15)}}}