<PRE><B>Question 672154</B>
&lt;br&gt;&lt;font face=&quot;Tahoma&quot;&gt;In this case, if P(E1)=.39 and P(E2)=.13,&lt;br&gt;

then it should be simple to find the rest.&lt;br&gt;

Why?  Because the sum of the probabilities for ALL 10 events must add up to EXACTLY 1.&lt;br&gt;

So, we have 8 equally probable events left.&lt;br&gt;

We also have {{{1-.39-.13}}} or .48 probability left to account for.&lt;br&gt;

So we just need to simply divide .48 by 8 since the 8 events are equally probable.&lt;br&gt;

So P(E3) and the probability of the other final 7 events is simply 0.06&lt;br&gt;

I hope this helps!  :)&lt;br&gt;

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