Question 672289
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Are you asking to solve for *[tex \LARGE w] in terms of everything else in the equation?  If that is what you mean, say so when you repost using parentheses to make it clear which parts of your RHS are in the denominator.  That is to say, do you mean a = 2/(6w) + 9, or do you mean a = 2/(6w + 9)?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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