Question 60819
Find the coordinates of the vertex of 
{{{y=2x^2}}}
When the quadratic formula is in standard form: {{{y=ax^2+bx+c}}}  the x-coordinate is found with the formula: {{{highlight(x=-b/2a)}}}
a=2, b=0, and c=0
{{{x=-(0)/(2(2))}}}
{{{x=-0/4}}}
{{{x=0}}}
That's the x-coordinate of the vertex.  You find the y coordinate by letting x=0.
{{{y=2(0)^2}}}
{{{y=2(0)}}}
y=0
The vertex is (x,y)=(0,0)
Happy Calculating!!!