Question 671876
x = 1, x = -2 or x = 2


x - 1 = 0, x + 2 = 0 or x - 2 = 0


(x - 1)(x + 2)(x - 2) = 0


(x - 1)(x^2 - 4) = 0


x(x^2 - 4) - 1(x^2 - 4) = 0


x^3 - 4x - x^2 + 4 = 0


x^3 - x^2 - 4x + 4 = 0


So the function is f(x) = x^3 - x^2 - 4x + 4, which is choice 4)