Question 638795
{{{2/3}}} + 3y = 5y - {{{2/15}}}
...
Isolate y
3y - 5y = {{{-2/15 - 2/3}}}
...
-2y = {{{-2/15 - (2/3)(5/5) = -2/15 - 10/15}}}
-2y = {{{-12/15}}}
...
y = {{{(-12/15)/-2 = (-12/15)(1/-2)}}}
{{{highlight_green(y = 6/15)}}}
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