Question 671702
let the integers be n,n+2,n+4

n^2+(n+2)^2=(n+4)^2+20

n^2+n^2+4n+4 =n^2+8n+16+20

2n^2+4n+4=n^2+8n+36

Rearrange
2n^2-n^2+4n-8n+4-36=0

n^2-4n-32=0

n^2-8n+4n-32=0

n(n-8)+4(n-8)=0
(n-8)(n+4)=0
n=8 OR -4

Ignore negative

the integers are 8 ,10,12