Question 671661
 {{{P(t)=Poe^(-kt)}}}

{{{ P(0)=92844e^(-kt)}}}

{{{P(45)=92844e^(-45k)}}}

{{{24974=92844e^(-45k)}}}

{{{24974/92844 =e^(-45k)}}}

{{{ln(24974/92844 ) = ln(e^(-45k))}}}

ln(24974/92844 ) = -45k.ln(e)

ln(24974/92844 ) = -45k

=0.02918
My calc gives this answr