Question 671091
16x + 8y > –32 using x and y-intercepts.

/8
2x+y>-32
y>-2x-32

We find the co ordinates by equating .
X intercept, plug y=0

16x=-32
/16
x=-2

(-2,0)

Y intercept plug x = 0

8y=-32
y=-4

(0,-4)

Equality

{{{drawing(300,300,-10,10,-10,10,circle(0,-4,0.3),circle(-2,0,0.3),graph(300,300,-10,10,-10,10,y=-2x-4))}}}


The Inequality

Since y is > than something the line will be a dotted one.

{{{drawing(300,300,-10,10,-10,10,circle(0,-4,0.3),circle(-2,0,0.3),graph(300,300,-10,10,-10,10,y>-2x-4))}}}