Question 60754
<pre>
This is a similar polygon question involving a pentagon. I couldn't find the
topic in Algebra but it's from an algebra class.

Need to find x of the segment vw

The two pentagons are similar. The first one the the sides for Q to R is 4 and
R to S is 3 and S to T is 5 and T to P is 3 and P to Q is 2. These sides will
somehow apply with the second pentagon. The sides that are suppose to be the
comparison for the VW I think is the PQ side. The other sides for the second
Pentagon that they want the first compared to and the side needs to be solved
for has points of W to X 6.4 and X to Y 4.8 and Y to Z is 8 and Z to V is 4.8.
Please help me solve the VW. I need to get this answer ASAP tonight. I have
been up most of the night trying to figure it out.
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Since pentagon PQRST is similar to pentagon VWXYZ, then

WX is to QR as XY is to RS, or
WX/QR = XY/RS
6.4/4 = 4.8/3
  1.6 = 1.6 

So if these pentagons are similar, then every side of pentagon VWXYZ is
1.6 times its corresponding side of pentagon PQRST.  Let's check to make
sure the given pentagons are really similar:

YZ should then be 1.6 times ST.  Sure enough, 8 = 1.6(5)

and

ZV should then be 1.6 times TP.  Sure enough, 4.8 = 1.6(3)

So VW must be 1.6 times PQ.  So VW = 1.6(PQ) = 1.6(2) = 3.2

That's the answer.  VW = 3.2

Edwin</pre>