Question 671092
Starting with
5(5x-4y) < 3(2+8x) - 17y
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distribute first
5(5x)-5(4y) < 3(2) + 3(8x) - 17y
25x- 20y < 6 + 18x - 17y
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Isolate y to one side of the equation
{{{cross(25x) - 20y - cross(25x) + highlight(17y) < 6 + 18x - cross(17y) + cross(17y) - highlight(25x)}}}
-20y + 17y < 6 + 18x - 25x
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Combine like terms
-3y < -7x + 6
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divide both sides by -3 (note sign change for dividing by a negative)
y > {{{-7x/3 + 6/-3}}} = {{{-7x/3 - 2}}}
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