Question 671032
Most importantly,
x cannont be >=0 to achieve greater than 4
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{{{sqrt(2*0) = 0}}}
0 + 2 = 2 which is not > 4
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The first answer takes care of the second.
x cannot be greater than 2 yet equal to or greater than zero.
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The first answer exludes 1, while the second answer includes it.
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You first answer was enough to solve the inequality
x > 2
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So long as x is > 2, it will always be > 0
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