Question 60730
Given that

2x - y =2           (1)
3z = 21            (2)
 4x + z =19      (3)
First solve the second equation, since it has only one variable.
3z =21
Divide by 3
z = 21/3
z =7

Now put the value of z in equation (3), we get
4x + 7 = 19
4x = 19 -7
4x =12
x =12/4
x = 3

Now put the value of x in equation(1), we get

2(3)- y =2 
6 – y = 2
6 – 2 = y
4 = y

Therefore the value of “x” =3, y =4 and z =7