Question 7561
This expression can be simplified as follows:

First, the numerator:

{{{3x^0 = 3(1)}}} Note that: {{{x^0 = 1}}}

Now the denominator:

{{{1/y^(-3) = y^3}}}

Putting it all together, we have:

{{{3x^0/y^(-3) = 3y^3}}}