Question 670704
{{{sqrt(2x-1) = sqrt(x-1) + 1}}}
Square both sides:


2x-1 = x-1 + 2sqrt(x-1) + 1

2x -1 = x + 2sqrt(x-1)


x -1 = 2sqrt(x-1)

Square both sides again:

x^2 - 2x + 1 = 4(x-1)

x^2 - 2x + 1 = 4x-4

x^2 -6x +5 = 0

(x-1)(x-5)

x = 1,5