Question 670641
You toss a ball from 5 feet. The ball's velocity is 30 feet per second. You catch the ball at 6 feet. How long is the ball in the air? 
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h(t) = -16t^2 + 30t + 5
Solve for t at h(t) = 6 feet
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h(t) = -16t^2 + 30t + 5 = 6
-16t^2 + 30t - 1 = 0
*[invoke solve_quadratic_equation -16,30,-1]
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The 1st solution is at 6 ft on its way up.
The 2nd is the total time requested.
t =~ 1.841 seconds