Question 670541
let the integers be x & y

xy=80
OR
x=80/y

x=3y+8

3y+8= 80/y

multiply equation by y
3y^2+8y=80
3y^2+8y-80=0
a=	3    	b=	8	c=	-80		
							
b^2-4ac=	64	-	-960				
b^2-4ac=	1024
{{{sqrt(	1024	)}}}=	32	
{{{y=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{y1=(-b+sqrt(b^2-4ac))/(2a)}}}				)/			
y1=(	-8	+	32	)/	6		
y1=	4						
y2=(	-8	-	32	)/	6		
y2=	-6.67						
Ignore negative value	it is not an integer						
y	=	4	

The integers are 4 & 20