<PRE><B>Question 670499</B>
Let	x be	the percent age of the mixyure								
	Percent	----------------			quantity					
Alcohol I	60	----------------			12	liters				
Alcohol II	25	----------------			8	liters				
Total	x	----------------			20	liters				
										
15*60+8	*25=20x
900+200	=20x				
1100=20x						
/	20								
1100	/	20	=	x					
55	=	x							
the percent age of the mixyure		is			55					
										
</PRE>