Question 670452
Two lines are perpendicular if the slope of one line is the negative reciprocal of the other slope of the other line.

First let's find the slope of the given line

3x + y = 1

y = 1 - 3x

slope = -3

the line perpendicular to the given line will then have a slope of {{{1/3}}}

Use the formula y - y1 = m(x - x1)

x1 = -2
y1 = 1

y - 1 = {{{1/3}}}(x - (-2))

y - 1 = {{{1/3}}}(x + 2)

y - 1 = {{{1/3}}}x + {{{2/3}}}

Then add 1 to both sides

y = {{{1/3}}}x + {{{5/3}}}