<PRE><B>Question 670326</B>
let x be the first number
let x + 1 be the second number

4 times the lesser number (which is x) is 8 more than 3 times the greater (which is x + 1)

4x = 8 + 3(x + 1)

4x = 8 + 3x + 3

4x = 11 + 3x

subtract 3x from both sides

x = 11

The second number is x + 1 = 11 + 1 = 12

So the consecutive numbers are 11 and 12</PRE>