Question 669998
One hour after a truck has left on an overnight haul, a messenger on a motorcycle
 leaves from the same starting point to overtake the truck.
 If the messenger travels at an average rate of 65 mi/hr and overtakes the truck
 in 4 hr, what is the average rate of the truck?
:
Let t = av rate of the truck (truck's travel time = 5 hrs)
:
When the bike overtakes the truck, they will have traveled the same distance
Write a distance equation; dist = rate * time
:
Truck dist = bike dist
5t = 4*65
5t = 260
t = {{{260/5}}}
t = 52 mph is the truck speed
:
:
Confirm this by finding the actual distance each traveled
Truck: 5(52) = 260 mi
Bike: 4(65) = 260 mi