Question 670143
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
 y = -2x^2
I. A parabola opening Downward
II. V(0,0) 
III.  Line of symmetry is the y=axis.
IV. Pt(1,-2) on the curve
{{{drawing(300,300,   -6, 6, -6, 6, grid(1),
circle(0, 0,0.3),
circle(1, -2,0.3),
graph( 300, 300, -6, 6, -6, 6,0,-2x^2))}}}
the vertex form of a Parabola opening up(a>0) or down(a<0), {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry