Question 670083
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Hi,
one positive integer{{{highlight(y)}}} is 5 less than 3 times another{{{highlight(x)}}} 
and their product is 78
Translate into an equation: 
  xy = 78     ||{{{y = 3x-5)}}}
 x(3x-5) = 78
 3x^2 - 5x - 78 = 0
factoring
(3x +13)(x - 6) = 0  x = 6   (throwing negative fractional solution)
two integers are: 6, 13