Question 670045
{{{3y^2=y+10}}}
{{{3y^2 - y - 10 = 0}}}
{{{(3y + 5)(y-2) = 0}}}
So either {{{(3y + 5)=0}}} or {{{(y-2)=0}}} 
Solve each of those for y to find the possible solutions
y = -5/3   or 2

You cna also use the quadratic formula to get the same answer
*[invoke quadratic "x", 3, -1, -10 ]