Question 670025
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<b>
Suppose, say, one die is red and the other green.
Here are all the possible rolls with a red die and a green die:
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(<font color="red">1</font>,<font color="green">1</font>) (<font color="red">1</font>,<font color="green">2</font>) (<font color="red">1</font>,<font color="green">3</font>) (<font color="red">1</font>,<font color="green">4</font>) (<font color="red">1</font>,<font color="green">5</font>) (<font color="red">1</font>,<font color="green">6</font>)
 
(<font color="red">2</font>,<font color="green">1</font>) (<font color="red">2</font>,<font color="green">2</font>) (<font color="red">2</font>,<font color="green">3</font>) (<font color="red">2</font>,<font color="green">4</font>) (<font color="red">2</font>,<font color="green">5</font>) (<font color="red">2</font>,<font color="green">6</font>) 

<b>(<font color="red">3</font>,<font color="green">1</font>)</b> (<font color="red">3</font>,<font color="green">2</font>) (<font color="red">3</font>,<font color="green">3</font>) (<font color="red">3</font>,<font color="green">4</font>) (<font color="red">3</font>,<font color="green">5</font>) (<font color="red">3</font>,<font color="green">6</font>)
 
(<font color="red">4</font>,<font color="green">1</font>) <b>(<font color="red">4</font>,<font color="green">2</font>)</b> (<font color="red">4</font>,<font color="green">3</font>) (<font color="red">4</font>,<font color="green">4</font>) (<font color="red">4</font>,<font color="green">5</font>) (<font color="red">4</font>,<font color="green">6</font>)
 
(<font color="red">5</font>,<font color="green">1</font>) (<font color="red">5</font>,<font color="green">2</font>) <b>(<font color="red">5</font>,<font color="green">3</font>)</b> (<font color="red">5</font>,<font color="green">4</font>) (<font color="red">5</font>,<font color="green">5</font>) (<font color="red">5</font>,<font color="green">6</font>)
 
(<font color="red">6</font>,<font color="green">1</font>) (<font color="red">6</font>,<font color="green">2</font>) (<font color="red">6</font>,<font color="green">3</font>) <b>(<font color="red">6</font>,<font color="green">4</font>) </b>(<font color="red">6</font>,<font color="green">5</font>) (<font color="red">6</font>,<font color="green">6</font>)
<b>
There are 36 possible rolls. The only rolls with have sum 11
are (5,6) and (6,5) So there are only 2 possible rolls out of
the 36 which have that property.

Therefore the probability is {{{2/36}}} 
which reduces to {{{1/18}}} = 0.056

Edwin</pre></b></font>









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