Question 669953
Work backward...
x = 1 +/- {{{sqrt(3)}}}
...
x - 1 =  +/- {{{sqrt(3)}}}
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{{{(x-1)^2 = sqrt(3)^2}}}
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{{{(x-1)^2 = 3}}}
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{{{x^2 - 2x + 1 = 3}}}
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{{{x^2 - 2x +1 - 1 = 3 - 1}}}
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{{{x^2 - 2x = 2}}}
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{{{highlight_green(x^2 - 2x - 2 = 0)}}}
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