Question 669760
A bag contains 6 pieces of fruit: a banana, two apples, an orange, and two pears. Two pieces of fruit are selected at random with replacement. Find the probability that both pieces are apples given that the first piece is an apple. Give your answer in fraction form.
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P(a|a) = P(a and a)/P(a) = (2/6)^2/(2/6) = 2/6 = 1/3
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Cheers,
Stan H.