Question 669690
First solve for y in each equation and get into slope intercept form


x+2y>-2


2y > -x-2


y > -(1/2)x-2/2


y > -(1/2)x-1


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3x+y < 3


y < - 3x + 3


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So after solving for y, we get 


y > -(1/2)x-1
y < - 3x + 3


Now graph the inequalities separately


To graph the inequality y > -(1/2)x-1, first graph the line y = -(1/2)x-1.


Make this line a dashed line.


Then shade above the dashed line.


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To graph the inequality y < - 3x + 3, first graph the line y = - 3x + 3.


Make this line a dashed line.


Then shade below the dashed line.


The final solution region will be the overlapping portion of the two individual shaded regions