Question 669667
Use the quadratic formula to solve for p


{{{p = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{p = (-(1)+-sqrt((1)^2-4(1)(4)))/(2(1))}}}


{{{p = (-1+-sqrt(1-(16)))/(2)}}}


{{{p = (-1+-sqrt(-15))/2}}}


{{{p = (-1+sqrt(-15))/2}}} or {{{p = (-1-sqrt(-15))/2}}}


{{{p = (-1+i*sqrt(15))/2}}} or {{{p = (-1-i*sqrt(15))/2}}}


Note: if you have NOT learned about complex/imaginary numbers yet, then you will simply say that there are no real solutions.