Question 7544
{{{4^2x+1}}}={{{2^3x+6}}}
16x+1=8x+6


Subtract 8x from both sides
(16x+1)-8x=(8x+6)-8x
8x+1=6


Subtract 1 from both sides
(8x+1)-1=(6)-1
8x=5


Divide both sides by 8
{{{8x/8}}}={{{5/8}}}
x={{{5/8}}}