Question 60672
Cosecutive integers are numbers which follow each other.
For example:  2, 3, 4, 5...are consecutive.
Similarly 39, 38, 37, 36, 35,.... are consecutive.
It follows that the integers have a difference of 1.
So let us take the 3 consecutive integers as (x-1), x,(x+1)

Twice the sum of the first and the third integers is
2[(x-1) + (x+1)]

This is 15 less than the second integer.
==> 2[(x-1) + (x+1)] = x - 15

==> 2(x-1+x+1) = x - 15
==> 2(2x) = x - 15
==> 4x = x - 15
==> 4x - x = -15
==> 3x = -15
==> 3x/3 = -15/3
==> x = -5
So the first integer is x - 1 = -5 -1
                              = -6

The second integer = x
                   = -5

The third integer = x+1
                  = -5 + 1
                  = - 4

The three consecutive integers are -6, -5, -4.


Good Luck!!!