Question 669559
Given the slope of a line is {{{-4/5}}} and a point on the line is (9,-7),
the equation of the line can be written in point-slope form as
{{{y-(-7)=(-4/5)(x-9)}}}
That form of the equation can be transformed (algebraically) into the unique slope-intercept form.
{{{y-(-7)=(-4/5)(x-9)}}} --> {{{y+7=(-4/5)x-9(-4/5)}}} --> {{{y+7=(-4/5)x+36/5}}}
The y-intercept is {{{highlight(36/5)=highlight(7&1/5)}}}