Question 666500
{{{x^2+8x=6}}}


{{{x^2+8x-6=0}}}


Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(8)+-sqrt((8)^2-4(1)(-6)))/(2(1))}}}


{{{x = (-8+-sqrt(64-(-24)))/(2)}}}


{{{x = (-8+-sqrt(64+24))/(2)}}}


{{{x = (-8+-sqrt(88))/2}}}


{{{x = (-8+sqrt(88))/2}}} or {{{x = (-8-sqrt(88))/2}}}


{{{x = (-8+2*sqrt(22))/2}}} or {{{x = (-8-2*sqrt(22))/2}}}


{{{x = -4+sqrt(22)}}} or {{{x = -4-sqrt(22)}}}


So the exact solutions are {{{x = -4+sqrt(22)}}} or {{{x = -4-sqrt(22)}}}