Question 669476
if log sub b of 3 = 0.4771, log sub b of 4 = 0.621, and log sub b of 5 = 0.6990, find the following logarithms:

1.) log sub b of 120
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{{{log(b,2) = log(b,4)/2 = 0.3105}}}
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120 = 2*3*4*5
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PS  log(4) = 0.6020, not 0.621 (base 10)